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Blog Module /

Discuss the Blog Module.

Moderators: martimiz, Sean, Ed, biapar, Willr, Ingo, swaiba

Add dataobject manager images through frontend


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3 Posts   3270 Views

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klikhier

Community Member, 150 Posts

18 June 2009 at 6:25am

Edited: 18/06/2009 6:28am

Hello, I have set up an ImageDateObjectManager that allows for adding multiple images to a BlogEntry through the CMS. My question: is it possible to add ONE image via www.website.com/blog/post?

Of course I can add the code below to function BlogEntryForm() in BlogHolder.php...

  new SimpleImageField('Image', 'Image (optional)'),

..but is it possible to use such a solution to add one photo through the frontend (myUrl/blog/post) that will be visible in the ImageDataObjectManager in the CMS?

Avatar
UncleCheese

Forum Moderator, 4102 Posts

18 June 2009 at 7:49am

Well before you go hacking the core code, I would create a BlogHolder subclass so you can safely overload the BlogEntryForm() function. What was the result when you added an image field to that? I think it may work fine, because the postblog() handler just runs $form->saveInto(), and I believe that takes into account your related objects and uploads. If not, just overload the postblog() function.

Avatar
klikhier

Community Member, 150 Posts

18 June 2009 at 9:38pm

Thanks UncleCheese, I started with SS as a designer, so forgive me my coding shortcuts (and the overloading) What I have right now:

Photo.php

class Photo extends DataObject
{
	static $db = array (
    'Caption' => 'Text'
	);

	static $has_one = array (
    'Image' => 'Image',
		'Page' => 'Page',
		'GalleryPage' => 'GalleryPage',
		'CalculatorPage' => 'CalculatorPage',
		'BlogHolder' => 'BlogHolder',
		'BlogEntry' => 'BlogEntry'
	);
	
	public function getCMSFields_forPopup()
	{
		return new FieldSet(
      new TextField('Caption','Name'),
			new ImageField('Image')
		);
	}

}

$has_many in BlogEntry.php

	static $has_many = array(
    'Photos' => 'Photo'
	);

Added to function BlogEntryForm() in BlogHolder.php

			
  new SimpleImageField('Photos', 'Image (optional)'),

This doesn't work? I don't fully understand what you mean with your latest sentence, so if you could... please help once more. Many thanks in advance!