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General questions about getting started with SilverStripe that don't fit in any of the categories above.

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Adding additional values to a DataObjectSet


3 Posts   530 Views


14 July 2011 at 12:10am (Last edited: 14 July 2011 12:11am), Community Member, 74 Posts

Hi All,

This is probably something really simple that I am missing here.

Basically building an item management system for frontend users to manage their own items. I have everything working fine except for one thing and I am sure it is something really simple that I just haven't found yet.

Essentially what I am asking is, is there a way to push a new column of data onto each row in a return DataObjectSet

So for example if I had FirstName (Colin) and Surname (Burns) and I wanted to create a new column called NickName which I created by the first letter of the FirstName and the Surname (cburns). I want know how to create this column in the logic and push it onto my DataObjectSet.

N.B: There is probably a way to do this specific example in the template, but that's not what i am looking for. I've deliberately tried to use a really simple example as a demonstration.

if(!isset($_GET['start']) || !is_numeric($_GET['start']) || (int)$_GET['start'] < 1) $_GET['start'] = 0;
$SQL_start = (int)$_GET['start'];
$AllItems = DataObject::get(
$callerClass = $thisClassName, // enter the Object type (e.g. 'MyPageType')
$filter = "ItemType = 'want' AND Status = '{$thisStatus}' AND MemberID = '".Member::currentUserID()."'",
$sort = "Created DESC, Value DESC",
$join = "",
$limit = "{$SQL_start}, $itemsPerPage" // enter the number of items per page (int)

// So I guess in here I would need to loop through the DataObjectSet using two of the fields in it to create a new field and then push it onto the DataObjectSet

return $this->customise(array('AllItems' => $AllItems))->renderWith('ajax_ListManagement_All');

Any suggestions would be grand :)



14 July 2011 at 12:24am (Last edited: 14 July 2011 12:24am), Forum Moderator, 1796 Posts

how about...

if ($AllItems) foreach ($AllItems as $item) {
$item->NickName = $item->FirstName.'_'.$item->Surname;

I do it all the time...


14 July 2011 at 12:30am Community Member, 74 Posts

Thanks for the reply, I will give it a shot.

I told you I thought it would be simple :)