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General Questions /

General questions about getting started with SilverStripe that don't fit in any of the categories above.

Moderators: martimiz, Sean, biapar, Willr, Ingo, swaiba, simon_w

How to show latest files uploaded to folder or one of it's subfolders


4 Posts   1766 Views


Community Member, 150 Posts

23 July 2011 at 4:14am

How can I show latest 5 files uploaded to a certain folder 'Public' OR uploaded to a subfolder of 'Public' OR uploaded to a subfolder of a subfolder of 'Public' and so on. Kind of like getChildrenAsUl, but than without the UL and LI and with a sort and limit function.


Community Member, 532 Posts

23 July 2011 at 7:53am

Okay here's an idea. It seems a little clunky to me and only offers two levels of recursion. but it'll work. I've tested it on a system with over 10000 files, its a little slow but it works. Maybe someone can find a way to make it more elegant/faster

   function LatestFiles() {
      //Use the ID for your "Public" folder for ParentID
      $files = new DataObjectSet();
      $folders = DataObject::get("Folder", "ParentID = X");
      if($folders) {
         //loop through folders
         foreach($folders as $folder){
            //check if folder has sub-folder
            if ($folder->hasChildFolders()){
               //get sub fodlers
               $subFolders = $folder->ChildFolders();
               //loop through sub folders
               foreach($subFolders as $subFolder) {
                  //check if has sub-sub folder
                  if ($subFolder->hasChildFolders()){
                     //get sub-sub folder
                     $subSubFolders = $subFolder->ChildFolders();
                     //push sub-sub folders to subfolder list
               //push sub fodler list to folder list
         //loop through all foldes to find files
         foreach($folders as $folder){
            $file = DataObject::get("File", "ClassName != 'Folder' AND ParentID=".$folder->ID);
      $files->sort("Created", "DSC");//reverse sort by date created
      return $files->getRange(0,5);//return first five in list


Forum Moderator, 1132 Posts

24 July 2011 at 7:43am

Edited: 24/07/2011 7:44am

Since the File table already 'knows' the path to each file in /assets/, in this case a straight query might get you there as well. Something like:

function NewPublicUploads() {
   return DataObject::get(
      $name = 'File',
      $filter = "ClassName = 'file' and Filename like 'assets/public/%'",
      $sort = "Created DESC",
      $join = "",
      $limit = "5"

<% if NewPublicUploads %>
   <% control NewPublicUploads %>
      <li><a href="$Filename">$Title.XML</a></li>
   <% end_control %>
<% end_if %>


Community Member, 150 Posts

24 July 2011 at 6:58pm

So simple... I guess I was trying to do it the hard way :) Many thanks Martimiz (and also zenmonkey; in this case I'll rate your answer as second-best :)