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General questions about getting started with SilverStripe that don't fit in any of the categories above.

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SS mySQL query halp

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3 Posts   1733 Views


Community Member, 26 Posts

6 October 2010 at 10:13am

So i'm a bit of a newbie having trouble with this sql query. I have a form in the cms that allows a user to input a vimeo video ID and then pass that to the vimeo moogaloop api.

So i've written a query the writes some xml to the head of the current videopage

$query = (int)DB::query("SELECT VimeoID FROM `VideoPage`WHERE `ID` = '$this->ID'")->value();

for some reason it keeps returning the value as 0. Any thoughts are appreciated.

$result = mysql_query($query);
$doc = new DomDocument('1.0');

// create root node
$root = $doc->createElement('vimeoURL');
$root = $doc->appendChild($root);

// add node for each row
$occ = $doc->createElement('vimeoURL');
$occ = $root->appendChild($occ);
$child = $doc->createElement('URL');
$child = $occ->appendChild($child);
$value = $doc->createTextNode('URL' + $result);
$value = $child->appendChild($value);

$xml_string = $doc->saveXML();
//header('Content-Type: application/xml; charset=ISO-8859-1');
echo $xml_string;


Forum Moderator, 1899 Posts

6 October 2010 at 11:26am

hi dan, is there a reason not to use DataObject::get_by_id?

$doVideoPage = DataObject::get_by_id('VideoPage',$this->ID);
 $occ = $doc->createElement($doVideoPage->vimeoURL); //assuming vimeoURL is in $db of $doVideoPage)


Community Member, 165 Posts

6 October 2010 at 3:02pm

If you really want to use SQLQuery, I think it would look more like this

$query = new SQLQuery();
$query->select = array("VimeoID");
$query->from = array("VideoPage");
$query->where = array("ID = $this->ID");

$result = $query->execute()->value();