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Moderators: martimiz, Sean, Ed, biapar, Willr, Ingo, swaiba

JQuery closest('tr') won't work

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4 Posts   4243 Views


Community Member, 33 Posts

2 March 2012 at 11:43pm

I have a table and when I click on a row, the childrows are opened in accordeon style with JQuery.
All works fine. But the only thing is, I want the accordeon to open a the level of the row I clicked.
Therefore, the function closest() is used. But this won't work.
My childtable always opens at the button of the mastertable...

I use the JQuery 1.6.4, so that can not be the problem.


Forum Moderator, 1391 Posts

3 March 2012 at 7:06am

Doesn't closest() travel up the tree? If so, it wouldn't open a child table. Maybe next() would work..

Anyway - not really a SilverStripe question :-)


Community Member, 33 Posts

3 March 2012 at 9:12pm

100% SS question.
I'm playing around with the JTable in SS. Really cool thing to work with.
All works fine, but there's just one thing I can't get right :
open the child table at the height of the parent table.

I suppose it's the SS framework and the way the page gets rendered. In ASP no problem.


Forum Moderator, 1391 Posts

5 March 2012 at 1:19am

Well, you didn't say that, did you? : -) You just said you had a table (somewhere), you click a row (= tr in my book) and closest() doesn't get you that same row (tr) - which it wouldn't, when you're clicking the row itself...

I suppose you're referring to something like this (from the jTable demo's):

$ () {
		{ ...

clicking this image inside a cell should definitelyget you the encompassing tr. Still: I don't see how this is a SilverStripe issue, unless of course you are trying to use this in the backend - or using some other interfering javascript on your frontend?