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Discuss SilverStripe Widgets.

Moderators: martimiz, Sean, Ed, biapar, Willr, Ingo, swaiba

Is there a way to get the ID of the containing page for a widget?

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2 Posts   2054 Views


Community Member, 35 Posts

19 May 2010 at 6:16am

Is there a simple, elegant way to obtain the ID of the page containing a widget, from within that widget?

I've figured out how to get the ID of the WidgetArea, but not the containing page.

Anyone have any ideas they could throw at me? For some reason this is more difficult than I first thought it would be...

class TestWidget extends Widget 
	static $db = array(
		'MyValue' => 'Varchar'

	static $title = "Test Widget";
	static $cmsTitle = "Test Widget Widget";
	static $description = "A widget to test with.";

	// Method to handle generation of form fields for selection of widget content
	function getCMSFields()
		$TxtFld = new TextField( "MyValue", "My Value" );	

		return new FieldSet( $TxtFld );

	function GetContainerPageID()
		return $this->parent()->ID;  // This only returns the ID of the WidgetArea...


Community Member, 78 Posts

19 May 2010 at 10:36pm


A widget knows it's parent WidgetArea, but the WidgetArea doesn't know it's owner. Typically a page that contains widgets will have:

static $has_one = array("Widgets" => "WidgetArea")

or something like that. So if you want the page that owns a particular widget area, you'll need to do something like this:

$page = DataObject::get_one("Page", "WidgetsID={$widgetAreaID}");

where $widgetAreaID is $this->parent()->ID within the widget, like you have in your function, and where WidgetsID is the column in page that has the widget area (the "Widgets" in the has_one, with "ID" added to the end)

In blog module, one of the primary consumers of widgets, BlogTree has this:

static $has_one = array(
"SideBar" => "WidgetArea",

so the column will be SideBarID. In this case it will be in the BlogTree and BlogTree_Live tables.

(you'll need to quote the filter in get_one properly for some databases - I'm assuming mysql)

Hope this helps